en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'-y/2 =e^{-t}

Solution

y^{^{'}} - \frac{y}{2} = e^{- t}

Solution

y = - \frac{2}{3 e ^{t}} + c_{1} e^{\frac{t}{2}}

Solution steps

y^{'} (t) - \frac{y}{2} = e^{- t}

Solve linear ODE:

y = - \frac{2}{3 e ^{t}} + c_{1} e^{\frac{t}{2}}

y = - \frac{2}{3 e ^{t}} + c_{1} e^{\frac{t}{2}}

Graph

Popular Examples

(e^x-y)dx+(e^y-x)dy=0

(e^{x} - y) d x + (e^{y} - x) d y = 0

(x+1)(dy)/(dx)=x+6

(x + 1) \frac{d y}{d x} = x + 6

integral of-2/(sqrt(100-9t^2))

\int - \frac{2}{100 - 9 t ^{2}} d t

limit as x approaches-1 of sin((pix)/6)

x \to - 1 lim (sin (\frac{π x}{6}))

integral of 4x^{3/2}

\int 4 x^{\frac{3}{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'-y/2 =e^{-t} ?
The solution for y^'-y/2 =e^{-t} is y=-2/(3e^t)+c_{1}e^{t/2}