What is (\partial)/(\partial y)(1-x-y) ?

The answer to (\partial)/(\partial y)(1-x-y) is -1

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(\partial)/(\partial y)(1-x-y)

\frac{\partial}{\partial y} (1 - x - y)

- 1

Solution steps

\frac{\partial}{\partial y} (1 - x - y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (1) - \frac{\partial}{\partial y} (x) - \frac{\partial}{\partial y} (y)

\frac{\partial}{\partial y} (1) = 0

\frac{\partial}{\partial y} (x) = 0

\frac{\partial}{\partial y} (y) = 1

= 0 - 0 - 1

Simplify

= - 1

x \to 0.1 lim (\frac{e ^{x} - 1}{x})

\int_{2}^{3} \frac{29}{3 - x} d x

f (x) = (6 x - x^{2})^{10}

\frac{d}{d x} (sin^{5} (3 x))

5 ln (x) + cos (x)

What is (\partial)/(\partial y)(1-x-y) ?
The answer to (\partial)/(\partial y)(1-x-y) is -1