What is the integral of (3^x+2/x) ?

The integral of (3^x+2/x) is (3^x)/(ln(3))+2ln|x|+C

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integral of (3^x+2/x)

\int (3^{x} + \frac{2}{x}) d x

\frac{3 ^{x}}{ln ( 3 )} + 2 ln ∣ x ∣ + C

Solution steps

\int 3^{x} + \frac{2}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3^{x} d x + \int \frac{2}{x} d x

\int 3^{x} d x = \frac{3 ^{x}}{ln ( 3 )}

\int \frac{2}{x} d x = 2 ln ∣ x ∣

= \frac{3 ^{x}}{ln ( 3 )} + 2 ln ∣ x ∣

Add a constant to the solution

= \frac{3 ^{x}}{ln ( 3 )} + 2 ln ∣ x ∣ + C

\int_{2}^{5} \frac{1}{x - 1} d x

\int x^{2} (2 x^{3} + 4)^{5} d x

\int \frac{x}{k} d x

x^{2} + x^{3} 1

(4 t^{2} - t) (t^{3} - 8 t^{2} + 12)

What is the integral of (3^x+2/x) ?
The integral of (3^x+2/x) is (3^x)/(ln(3))+2ln|x|+C