What is the tangent of x^2-xy+y^2=3,(1,2) ?

The tangent of x^2-xy+y^2=3,(1,2) is y=2

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tangent of x^2-xy+y^2=3,(1,2)

tangent of

x^{2} - x y + y^{2} = 3, (1, 2)

y = 2

Solution steps

Find the slope of

x^{2} - x y + y^{2} = 3 : \frac{d y}{d x} = \frac{- 2 x + y}{- x + 2 y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(1, 2) : y = 2

y = 2

\frac{4 x ^{5} + 5}{x ^{3}}

y^{^{'}} = x y^{2}

\frac{d}{d x} (e^{x} sin (x) cos (x))

\frac{d}{d x} (\frac{1}{x} + \frac{1}{y})

y^{^{''}} + (y^{^{'}})^{2} = 0

What is the tangent of x^2-xy+y^2=3,(1,2) ?
The tangent of x^2-xy+y^2=3,(1,2) is y=2