What is the solution for f^'(x)=(3x^5-2)^{20} ?

The solution for f^'(x)=(3x^5-2)^{20} is f(x)=integral of (3x^5-2)^{20}

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f^'(x)=(3x^5-2)^{20}

f^{^{'}} (x) = (3 x^{5} - 2)^{20}

f (x) = \int (3 x^{5} - 2)^{20} d x

Solution steps

f^{'} (x) = (3 x^{5} - 2)^{20}

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

f (x) = \int (3 x^{5} - 2)^{20} d x

f (x) = \int (3 x^{5} - 2)^{20} d x

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\frac{\partial}{\partial y} (x^{2} - y^{3} - x^{2} y + y)

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What is the solution for f^'(x)=(3x^5-2)^{20} ?
The solution for f^'(x)=(3x^5-2)^{20} is f(x)=integral of (3x^5-2)^{20}