What is the derivative of x^3+2x+1 ?

The derivative of x^3+2x+1 is 3x^2+2

What is the first derivative of x^3+2x+1 ?

The first derivative of x^3+2x+1 is 3x^2+2

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\frac{d}{d x} (x^{3} + 2 x + 1)

3 x^{2} + 2

Solution steps

\frac{d}{d x} (x^{3} + 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 3 x^{2} + 2 + 0

Simplify

= 3 x^{2} + 2

\int sin (3 x + 2) d x

y = 4 x cos (x), at x = π

\int \frac{1}{csc ^{2} ( x )} d x

(2.1) (8.7)

\frac{\partial}{\partial x} (sin (3 x - 2 y))

What is the derivative of x^3+2x+1 ?
The derivative of x^3+2x+1 is 3x^2+2
What is the first derivative of x^3+2x+1 ?
The first derivative of x^3+2x+1 is 3x^2+2