What is (\partial)/(\partial x)(6xyz) ?

The answer to (\partial)/(\partial x)(6xyz) is 6yz

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(\partial)/(\partial x)(6xyz)

\frac{\partial}{\partial x} (6 x yz)

6 yz

Solution steps

\frac{\partial}{\partial x} (6 x yz)

Treat

y, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 yz \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 6 yz \cdot 1

Simplify

= 6 yz

\frac{d}{d x} (-, x)

(- 8, - 9), (- 5, - 3)

\int ln (x) y d x

\int x e^{7 x^{2}} d x

\frac{d}{d x} (x 81 - x^{2})

What is (\partial)/(\partial x)(6xyz) ?
The answer to (\partial)/(\partial x)(6xyz) is 6yz