What is the integral from-infinity to 10 of re^{r/5} ?

The integral from-infinity to 10 of re^{r/5} is 25e^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-infinity to 10 of re^{r/5}

\int_{- \infty}^{10} r e^{\frac{r}{5}} d r

25 e^{2}

Decimal Notation

184.72640 \dots

Solution steps

\int_{- \infty}^{10} r e^{\frac{r}{5}} d r

Compute the indefinite integral:

\int r e^{\frac{r}{5}} d r = 5 e^{\frac{r}{5}} r - 25 e^{\frac{r}{5}} + C

Compute the boundaries:

\int_{- \infty}^{10} r e^{\frac{r}{5}} d r = 25 e^{2} - 0

= 25 e^{2} - 0

Simplify

= 25 e^{2}

x \to \infty lim (2^{+ x})

\int x ln (x) d x

\frac{d}{d x} ((2 - x^{2})^{\frac{1}{2}})

\int (tan (x))^{5} d x

\frac{d}{d x} (ln (1 + x^{3}))

What is the integral from-infinity to 10 of re^{r/5} ?
The integral from-infinity to 10 of re^{r/5} is 25e^2