What is the derivative of (y^2/(b^2)) ?

The derivative of (y^2/(b^2)) is (2y\frac{dy)/(dx)}{b^2}

What is the first derivative of (y^2/(b^2)) ?

The first derivative of (y^2/(b^2)) is (2y\frac{dy)/(dx)}{b^2}

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\frac{d}{d x} (\frac{y ^{2}}{b ^{2}})

\frac{2 y \frac{d y}{d x}}{b ^{2}}

Solution steps

\frac{d}{d x} (\frac{y ^{2}}{b ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{b ^{2}} \frac{d}{d x} (y^{2})

Apply the chain rule:

2 y \frac{d y}{d x}

= 2 y \frac{d y}{d x}

Simplify

\frac{1}{b ^{2}} \cdot 2 y \frac{d y}{d x} : \frac{2 y \frac{d y}{d x}}{b ^{2}}

= \frac{2 y \frac{d y}{d x}}{b ^{2}}

\frac{d}{d x} (20 cos (2 x) - 30 sin (2 x))

\int 8 sin (2 x) d x

\frac{d ^{2} x}{d t ^{2}}

\frac{\partial}{\partial x} (x e^{y} - yz)

\int_{0}^{\frac{π}{2}} (5 cos^{2} (x)) d x

What is the derivative of (y^2/(b^2)) ?
The derivative of (y^2/(b^2)) is (2y\frac{dy)/(dx)}{b^2}
What is the first derivative of (y^2/(b^2)) ?
The first derivative of (y^2/(b^2)) is (2y\frac{dy)/(dx)}{b^2}