What is the derivative of tan(x+c) ?

The derivative of tan(x+c) is sec^2(x+c)

What is the first derivative of tan(x+c) ?

The first derivative of tan(x+c) is sec^2(x+c)

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\frac{d}{d x} (tan (x + c))

sec^{2} (x + c)

Solution steps

\frac{d}{d x} (tan (x + c))

Apply the chain rule:

sec^{2} (x + c) \frac{d}{d x} (x + c)

= sec^{2} (x + c) \frac{d}{d x} (x + c)

\frac{d}{d x} (x + c) = 1

= sec^{2} (x + c) \cdot 1

Simplify

= sec^{2} (x + c)

\int \frac{( x ^{3} + 20 x ^{2} + 8 )}{x + 20} d x

\int 7 e^{x^{2}} d x

\int x^{1} e^{x} d x

\int (6 x + 4) d x

6 y^{^{''}} + 3 y^{^{'}} = 0

What is the derivative of tan(x+c) ?
The derivative of tan(x+c) is sec^2(x+c)
What is the first derivative of tan(x+c) ?
The first derivative of tan(x+c) is sec^2(x+c)