What is the integral of 1/(sin(x)*cos(x)) ?

The integral of 1/(sin(x)*cos(x)) is ln|tan(x)|+C

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integral of 1/(sin(x)*cos(x))

\int \frac{1}{sin ( x ) \cdot cos ( x )} d x

ln ∣ tan (x) ∣ + C

Solution steps

\int \frac{1}{sin ( x ) cos ( x )} d x

Rewrite using trig identities

= \int \frac{sec ( x )}{sin ( x )} d x

Apply Trigonometric Substitution

: \int \frac{1}{u} d u

= \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= ln ∣ u ∣

Substitute back

u = tan (x)

= ln ∣ tan (x) ∣

Add a constant to the solution

= ln ∣ tan (x) ∣ + C

\int_{1}^{\infty} 9 e^{- 3 x} d x

y = 5 (x^{2} + 2 x)^{3}

\frac{d}{d x} (- ln (2) \cdot 2^{- x})

\int_{0}^{3} x x + 1 d x

f (x) = 9 x - 8 x, at x = 1

What is the integral of 1/(sin(x)*cos(x)) ?
The integral of 1/(sin(x)*cos(x)) is ln|tan(x)|+C