What is the derivative of ((4x+asqrt(1+x))/(x^2-1)) ?

The derivative of ((4x+asqrt(1+x))/(x^2-1)) is (-8x^2-3axsqrt(x+1)-asqrt(x+1)-8)/(2(x^2-1)^2)

What is the first derivative of ((4x+asqrt(1+x))/(x^2-1)) ?

The first derivative of ((4x+asqrt(1+x))/(x^2-1)) is (-8x^2-3axsqrt(x+1)-asqrt(x+1)-8)/(2(x^2-1)^2)

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\frac{d}{d x} (\frac{( 4 x + a 1 + x )}{x ^{2} - 1})

\frac{- 8 x ^{2} - 3 a x x + 1 - a x + 1 - 8}{2 ( x ^{2} - 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{( 4 x + a 1 + x )}{x ^{2} - 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 4 x + a 1 + x ) ( x ^{2} - 1 ) - \frac{d}{d x} ( x ^{2} - 1 ) ( 4 x + a 1 + x )}{( x ^{2} - 1 ) ^{2}}

\frac{d}{d x} (4 x + a 1 + x) = 4 + \frac{a}{2 1 + x}

\frac{d}{d x} (x^{2} - 1) = 2 x

= \frac{( 4 + \frac{a}{2 1 + x} ) ( x ^{2} - 1 ) - 2 x ( 4 x + a 1 + x )}{( x ^{2} - 1 ) ^{2}}

Simplify

\frac{( 4 + \frac{a}{2 1 + x} ) ( x ^{2} - 1 ) - 2 x ( 4 x + a 1 + x )}{( x ^{2} - 1 ) ^{2}} : \frac{- 8 x ^{2} - 3 a x x + 1 - a x + 1 - 8}{2 ( x ^{2} - 1 ) ^{2}}

= \frac{- 8 x ^{2} - 3 a x x + 1 - a x + 1 - 8}{2 ( x ^{2} - 1 ) ^{2}}

\frac{16}{( s - 1 ) ( s + 1 )}

\frac{2}{s ^{2} ( s ^{2} + 25 )}

\frac{\partial}{\partial x} (4 y sin (2 x))

e^{y} y^{^{'}} = e^{y} + 7 x

\int x sin (2 x^{2}) d x

What is the derivative of ((4x+asqrt(1+x))/(x^2-1)) ?
The derivative of ((4x+asqrt(1+x))/(x^2-1)) is (-8x^2-3axsqrt(x+1)-asqrt(x+1)-8)/(2(x^2-1)^2)
What is the first derivative of ((4x+asqrt(1+x))/(x^2-1)) ?
The first derivative of ((4x+asqrt(1+x))/(x^2-1)) is (-8x^2-3axsqrt(x+1)-asqrt(x+1)-8)/(2(x^2-1)^2)