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Popular >

derivative of ln(x^2-x)

Solution

\frac{d}{d x} (ln (x^{2} - x))

Solution

\frac{2 x - 1}{x ^{2} - x}

Solution steps

\frac{d}{d x} (ln (x^{2} - x))

Apply the chain rule:

\frac{1}{x ^{2} - x} \frac{d}{d x} (x^{2} - x)

= \frac{1}{x ^{2} - x} \frac{d}{d x} (x^{2} - x)

\frac{d}{d x} (x^{2} - x) = 2 x - 1

= \frac{1}{x ^{2} - x} (2 x - 1)

Simplify

\frac{1}{x ^{2} - x} (2 x - 1) : \frac{2 x - 1}{x ^{2} - x}

= \frac{2 x - 1}{x ^{2} - x}

Popular Examples

tangent of y=-3cos(x),\at x=(-pi)/3 tangent of

y = - 3 cos (x), at x = \frac{- π}{3}

(e^y+1)^2e^{-y}dx+(e^x+1)^3dy=0

(e^{y} + 1)^{2} e^{- y} d x + (e^{x} + 1)^{3} d y = 0

integral of 4e^x+12x^3+4x

\int 4 e^{x} + 12 x^{3} + 4 x d x

tangent of f(x)=2sin(x),\at x= pi/4 tangent of

f (x) = 2 sin (x), at x = \frac{π}{4}

slope of (5.2)(-9.6)slope

(5.2) (- 9.6)

Frequently Asked Questions (FAQ)

What is the derivative of ln(x^2-x) ?
The derivative of ln(x^2-x) is (2x-1)/(x^2-x)
What is the first derivative of ln(x^2-x) ?
The first derivative of ln(x^2-x) is (2x-1)/(x^2-x)