What is the tangent of y=-3cos(x),\at x=(-pi)/3 ?

The tangent of y=-3cos(x),\at x=(-pi)/3 is y=-(3sqrt(3))/2 x+(-3-sqrt(3)pi)/2

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tangent of y=-3cos(x),\at x=(-pi)/3

tangent of

y = - 3 cos (x), at x = \frac{- π}{3}

y = - \frac{3 3}{2} x + \frac{- 3 - 3 π}{2}

Solution steps

Find the tangent point:

(\frac{- π}{3}, - \frac{3}{2})

Find the slope of

y = - 3 cos (x) : \frac{d y}{d x} = 3 sin (x)

Compute the slope of

y = - 3 cos (x)

x = \frac{- π}{3} : m = - \frac{3 3}{2}

Find the line with slope m=

- \frac{3 3}{2}

and passing through

(\frac{- π}{3}, - \frac{3}{2}) : y = - \frac{3 3}{2} x + \frac{- 3 - 3 π}{2}

y = - \frac{3 3}{2} x + \frac{- 3 - 3 π}{2}

(e^{y} + 1)^{2} e^{- y} d x + (e^{x} + 1)^{3} d y = 0

\int 4 e^{x} + 12 x^{3} + 4 x d x

f (x) = 2 sin (x), at x = \frac{π}{4}

(5.2) (- 9.6)

e^{x^{2} - x}

What is the tangent of y=-3cos(x),\at x=(-pi)/3 ?
The tangent of y=-3cos(x),\at x=(-pi)/3 is y=-(3sqrt(3))/2 x+(-3-sqrt(3)pi)/2