What is implicit 5x^2+y^2=9 ?

The answer to implicit 5x^2+y^2=9 is (dy}{dx}=-\frac{5x)/y

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implicit 5x^2+y^2=9

implicit derivative

5 x^{2} + y^{2} = 9

\frac{d y}{d x} = - \frac{5 x}{y}

Solution steps

5 x^{2} + y^{2} = 9

Treat

y

y (x)

Differentiate both sides:

10 x + 2 y \frac{d y}{d x} = 0

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = - \frac{5 x}{y}

\frac{d y}{d x} = - \frac{5 x}{y}

\int x^{3} x + 1 d x

y^{^{''}} - 2 y^{^{'}} - 24 y = 0

\int x^{3} (x^{4} + 3)^{3} d x

\int 4^{(8 - 2 x)} d x

\int (\frac{4 x ^{4} - 6 x ^{2}}{x}) d x

What is implicit 5x^2+y^2=9 ?
The answer to implicit 5x^2+y^2=9 is (dy}{dx}=-\frac{5x)/y