What is the integral of x^3(x^4+3)^3 ?

The integral of x^3(x^4+3)^3 is (x^{16}}{16}+\frac{3x^{12})/4+(27x^8)/8+(27x^4)/4+C

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integral of x^3(x^4+3)^3

\int x^{3} (x^{4} + 3)^{3} d x

\frac{x ^{16}}{16} + \frac{3 x ^{12}}{4} + \frac{27 x ^{8}}{8} + \frac{27 x ^{4}}{4} + C

Solution steps

\int x^{3} (x^{4} + 3)^{3} d x

Expand

x^{3} (x^{4} + 3)^{3} : x^{15} + 9 x^{11} + 27 x^{7} + 27 x^{3}

= \int x^{15} + 9 x^{11} + 27 x^{7} + 27 x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{15} d x + \int 9 x^{11} d x + \int 27 x^{7} d x + \int 27 x^{3} d x

\int x^{15} d x = \frac{x ^{16}}{16}

\int 9 x^{11} d x = \frac{3 x ^{12}}{4}

\int 27 x^{7} d x = \frac{27 x ^{8}}{8}

\int 27 x^{3} d x = \frac{27 x ^{4}}{4}

= \frac{x ^{16}}{16} + \frac{3 x ^{12}}{4} + \frac{27 x ^{8}}{8} + \frac{27 x ^{4}}{4}

Add a constant to the solution

= \frac{x ^{16}}{16} + \frac{3 x ^{12}}{4} + \frac{27 x ^{8}}{8} + \frac{27 x ^{4}}{4} + C

\int 4^{(8 - 2 x)} d x

\int (\frac{4 x ^{4} - 6 x ^{2}}{x}) d x

\int (x^{2} ln (2 x)) d x

e^{x^{2}} - 1

What is the integral of x^3(x^4+3)^3 ?
The integral of x^3(x^4+3)^3 is (x^{16}}{16}+\frac{3x^{12})/4+(27x^8)/8+(27x^4)/4+C