What is the limit as h approaches 0 of (cosh(x))/h ?

The limit as h approaches 0 of (cosh(x))/h is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as h approaches 0 of (cosh(x))/h

h \to 0 lim (\frac{cosh ( x )}{h})

diverges

Solution steps

h \to 0 lim (\frac{cosh ( x )}{h})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

h \to 0 + lim (\frac{cosh ( x )}{h}) = \infty

h \to 0 - lim (\frac{cosh ( x )}{h}) = - \infty

= diverges

\int \frac{9}{x ^{2} + 16} d x

\int \frac{1 - tan ^{2} ( x )}{sec ^{2} ( x )} d x

\frac{x ^{2}}{3 + x}

ln (1 + x), 3

\int \frac{3}{x ^{2}} + \frac{2}{x ^{3}} d x

What is the limit as h approaches 0 of (cosh(x))/h ?
The limit as h approaches 0 of (cosh(x))/h is diverges