What is (\partial)/(\partial y)(-sin(x)sin(y)) ?

The answer to (\partial)/(\partial y)(-sin(x)sin(y)) is -sin(x)cos(y)

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(\partial)/(\partial y)(-sin(x)sin(y))

\frac{\partial}{\partial y} (- sin (x) sin (y))

- sin (x) cos (y)

Solution steps

\frac{\partial}{\partial y} (- sin (x) sin (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - sin (x) \frac{\partial}{\partial y} (sin (y))

Apply the common derivative:

\frac{\partial}{\partial y} (sin (y)) = cos (y)

= - sin (x) cos (y)

n = 0 \sum \infty \frac{( x ^{n} )}{n}

\frac{d y}{y ln ( \frac{k}{y} )} = c d x

(2 x + 1)^{10}

\int_{0}^{\infty} e^{- 2 x^{2}} d x

What is (\partial)/(\partial y)(-sin(x)sin(y)) ?
The answer to (\partial)/(\partial y)(-sin(x)sin(y)) is -sin(x)cos(y)