What is laplacetransform 5e^{2t} ?

The answer to laplacetransform 5e^{2t} is 5/(s-2)

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laplacetransform 5e^{2t}

laplace transform

5 e^{2 t}

\frac{5}{s - 2}

Solution steps

L {5 e^{2 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 5 L {e^{2 t}}

L {e^{2 t}} : \frac{1}{s - 2}

= 5 \cdot \frac{1}{s - 2}

Refine

5 \frac{1}{s - 2} : \frac{5}{s - 2}

= \frac{5}{s - 2}

\frac{d}{d x} (\frac{1}{2 1 + x})

\frac{\partial}{\partial x} (x^{2} - 2 x y + 2 y^{2} + x - 2 y)

\frac{d}{d x} (cos (π \cdot x))

x^{2} \cdot e^{x} + 4 \cdot y \cdot e^{(- y)} \cdot y^{^{'}} = 0

\frac{d}{d x} ((x - 1) ln (x - 1))

What is laplacetransform 5e^{2t} ?
The answer to laplacetransform 5e^{2t} is 5/(s-2)