What is the integral from 0 to x^2 of t^2 ?

The integral from 0 to x^2 of t^2 is (x^6)/3

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integral from 0 to x^2 of t^2

\int_{0}^{x^{2}} t^{2} d t

\frac{x ^{6}}{3}

Solution steps

\int_{0}^{x^{2}} t^{2} d t

Apply the Power Rule

: [\frac{t ^{3}}{3}]_{0}^{x^{2}}

= [\frac{t ^{3}}{3}]_{0}^{x^{2}}

Compute the boundaries:

\frac{x ^{6}}{3}

= \frac{x ^{6}}{3}

y = 5 x^{4} - x^{2} + 6

\frac{d}{d x} (2 x + 9)

\int \frac{4 x ^{3} + 2 x ^{2} + 1}{4 x ^{3} - x} d x

(x^{3} + 6) e^{x}

\frac{d}{d x} (lo g_{3} (4 x - 3))

What is the integral from 0 to x^2 of t^2 ?
The integral from 0 to x^2 of t^2 is (x^6)/3