What is the tangent of f(x)=5e^x,\at x=4 ?

The tangent of f(x)=5e^x,\at x=4 is y=5e^4x-15e^4

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tangent of f(x)=5e^x,\at x=4

tangent of

f (x) = 5 e^{x}, at x = 4

y = 5 e^{4} x - 15 e^{4}

Solution steps

Find the tangent point:

(4, 5 e^{4})

Find the slope of

f (x) = 5 e^{x} : \frac{df ( x )}{d x} = 5 e^{x}

Compute the slope of

f (x) = 5 e^{x}

x = 4 : m = 5 e^{4}

Find the line with slope m=

5 e^{4}

and passing through

(4, 5 e^{4}) : y = 5 e^{4} x - 15 e^{4}

y = 5 e^{4} x - 15 e^{4}

\int (sin (2 x))^{3} d x

\int (\frac{1}{x ^{3} + 1}) d x

x (2 x + 1)^{3}

\frac{d}{d x} (sinh^{2} (3 x) + arcsin (2 x))

\int (3 x^{3} + (2 x - 3)^{2}) d x

What is the tangent of f(x)=5e^x,\at x=4 ?
The tangent of f(x)=5e^x,\at x=4 is y=5e^4x-15e^4