What is the slope ofintercept (4,-2),(-8,-1) ?

The slope ofintercept (4,-2),(-8,-1) is y=-1/12 x-5/3

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slope ofintercept (4,-2),(-8,-1)

slope intercept

(4, - 2), (- 8, - 1)

y = - \frac{1}{12} x - \frac{5}{3}

Solution steps

Compute the slope

(4, - 2), (- 8, - 1) : m = - \frac{1}{12}

Compute the

y

intercept:

b = - \frac{5}{3}

Construct the line equation

y = mx + b

where

m = - \frac{1}{12}

and

b = - \frac{5}{3}

y = - \frac{1}{12} x - \frac{5}{3}

x \to 3 lim (25 - x^{2})

y = sin (tan (6 x))

\frac{\partial}{\partial y} (x y + ln (y) + 2 x^{2})

\frac{\partial}{\partial x} (cos^{3} (x) y - 1)

\frac{s ^{2}}{( s ^{2} + 4 ) ^{2}}

What is the slope ofintercept (4,-2),(-8,-1) ?
The slope ofintercept (4,-2),(-8,-1) is y=-1/12 x-5/3