What is the derivative of (3x+1^2) ?

The derivative of (3x+1^2) is 6(3x+1)

What is the first derivative of (3x+1^2) ?

The first derivative of (3x+1^2) is 6(3x+1)

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\frac{d}{d x} ((3 x + 1)^{2})

6 (3 x + 1)

Solution steps

\frac{d}{d x} ((3 x + 1)^{2})

Apply the chain rule:

2 (3 x + 1) \frac{d}{d x} (3 x + 1)

= 2 (3 x + 1) \frac{d}{d x} (3 x + 1)

\frac{d}{d x} (3 x + 1) = 3

= 2 (3 x + 1) \cdot 3

Simplify

= 6 (3 x + 1)

\frac{d}{d x} (\frac{e ^{2 - 3 x}}{x ^{2}})

\frac{( s ^{2} - 4 s + 20 )}{( s + 2 ) ( s + 4 )}

\int (6 e^{- 0.1 x}) d x

\frac{d}{d x} (\frac{x ^{2} + 2 x - 3}{( x + 1 ) ^{2}})

x \to - 4 lim (\frac{x ^{2} - 6}{4 - x})

What is the derivative of (3x+1^2) ?
The derivative of (3x+1^2) is 6(3x+1)
What is the first derivative of (3x+1^2) ?
The first derivative of (3x+1^2) is 6(3x+1)