What is the d/(dθ)(sin(θ)+csc(θ)) ?

The d/(dθ)(sin(θ)+csc(θ)) is cos(θ)-cot(θ)csc(θ)

What is the first d/(dθ)(sin(θ)+csc(θ)) ?

The first d/(dθ)(sin(θ)+csc(θ)) is cos(θ)-cot(θ)csc(θ)

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\frac{d}{d θ} (sin (θ) + csc (θ))

cos (θ) - cot (θ) csc (θ)

Solution steps

\frac{d}{d θ} (sin (θ) + csc (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (sin (θ)) + \frac{d}{d θ} (csc (θ))

\frac{d}{d θ} (sin (θ)) = cos (θ)

\frac{d}{d θ} (csc (θ)) = - cot (θ) csc (θ)

= cos (θ) - cot (θ) csc (θ)

x \to \frac{π}{2} lim (5 sec (x))

\frac{d}{d x} (\frac{x ^{3} y - x y ^{3}}{x ^{2} + y ^{2}})

\frac{\partial}{\partial x} (z^{3} x^{2} e^{z x} + x^{2} z)

y^{^{'}} (y - x) = 1

\int - x \cdot ln (x) d x

What is the d/(dθ)(sin(θ)+csc(θ)) ?
The d/(dθ)(sin(θ)+csc(θ)) is cos(θ)-cot(θ)csc(θ)
What is the first d/(dθ)(sin(θ)+csc(θ)) ?
The first d/(dθ)(sin(θ)+csc(θ)) is cos(θ)-cot(θ)csc(θ)