What is the integral from-1 to 2 of (-y^2+y+2) ?

The integral from-1 to 2 of (-y^2+y+2) is 9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 2 of (-y^2+y+2)

\int_{- 1}^{2} (- y^{2} + y + 2) d y

\frac{9}{2}

Decimal Notation

4.5

Solution steps

\int_{- 1}^{2} - y^{2} + y + 2 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{2} y^{2} d y + \int_{- 1}^{2} y d y + \int_{- 1}^{2} 2 d y

\int_{- 1}^{2} y^{2} d y = 3

\int_{- 1}^{2} y d y = \frac{3}{2}

\int_{- 1}^{2} 2 d y = 6

= - 3 + \frac{3}{2} + 6

Simplify

- 3 + \frac{3}{2} + 6 : \frac{9}{2}

= \frac{9}{2}

x^{3} cos (x^{2})

\int \frac{x ^{2}}{25 - 9 x ^{2}} d x

2 y^{^{''}} - 9 y^{^{'}} - 5 y = 0

sec^{2} (π x)

\frac{d}{d x} (\frac{6}{x + 2})

What is the integral from-1 to 2 of (-y^2+y+2) ?
The integral from-1 to 2 of (-y^2+y+2) is 9/2