What is the integral of cos(x)(4+4sin^2(x)) ?

The integral of cos(x)(4+4sin^2(x)) is 4sin(x)+(4sin^3(x))/3+C

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integral of cos(x)(4+4sin^2(x))

\int cos (x) (4 + 4 sin^{2} (x)) d x

4 sin (x) + \frac{4 sin ^{3} ( x )}{3} + C

Solution steps

\int cos (x) (4 + 4 sin^{2} (x)) d x

Apply u-substitution

: \int 4 + 4 u^{2} d u

= \int 4 + 4 u^{2} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 d u + \int 4 u^{2} d u

\int 4 d u = 4 u

\int 4 u^{2} d u = \frac{4 u ^{3}}{3}

= 4 u + \frac{4 u ^{3}}{3}

Substitute back

u = sin (x)

= 4 sin (x) + \frac{4 sin ^{3} ( x )}{3}

Add a constant to the solution

= 4 sin (x) + \frac{4 sin ^{3} ( x )}{3} + C

x \to 0 lim (\frac{x - x}{x ^{2}})

\frac{d}{d x} ((x + 1) ln^{2} (x + 1))

y = x (x^{2} + 1)

f (y) = cos^{2} (y)

\int sec^{4} (5 x) tan^{3} (5 x) d x

What is the integral of cos(x)(4+4sin^2(x)) ?
The integral of cos(x)(4+4sin^2(x)) is 4sin(x)+(4sin^3(x))/3+C