What is area f(x)=xsin(x),0,2pi ?

The answer to area f(x)=xsin(x),0,2pi is 4pi

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area f(x)=xsin(x),0,2pi

area

f (x) = x sin (x), 0, 2 π

4 π

Solution steps

Apply the area formula:

\int_{0}^{2 π} ∣ x ∣ ∣ sin (x) ∣ d x

Solve

\int_{0}^{2 π} ∣ x ∣ ∣ sin (x) ∣ d x : 4 π

The area is:

= 4 π

\frac{d}{d x} ((- 3 x + 2)^{4} (- 2 x + 3)^{3})

f (x) = x - 5

y^{^{''}} + 2 y^{^{'}} + y = sin (x) + 4 cos (2 x)

(y + 4) \cdot \frac{d y}{d x} = 2 x y + 4 y

x \to π lim (- csc (2 x))