What is the solution for (dy)/(dx)=2xe^{4y} ?

The solution for (dy)/(dx)=2xe^{4y} is y=-(ln(-4x^2-c_{1}))/4

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(dy)/(dx)=2xe^{4y}

\frac{d y}{d x} = 2 x e^{4 y}

y = - \frac{ln ( - 4 x ^{2} - c _{1} )}{4}

Solution steps

\frac{d y}{d x} = 2 x e^{4 y}

Solve separable ODE:

y = - \frac{ln ( - 4 x ^{2} - c _{1} )}{4}

y = - \frac{ln ( - 4 x ^{2} - c _{1} )}{4}

y^{^{''}} - 2 y^{^{'}} + y = - 6 - 3 x + \frac{2 e ^{x}}{x}

\frac{d}{d x} (ln (x^{2} e^{x^{2 + 1}}))

\int cot^{5} (x) csc^{2} (x) d x

\int_{2}^{5} t^{4} ln (2 t) d t

x \to 0 lim ((1 + \frac{4}{x ^{4}})^{x})

What is the solution for (dy)/(dx)=2xe^{4y} ?
The solution for (dy)/(dx)=2xe^{4y} is y=-(ln(-4x^2-c_{1}))/4