What is the derivative of x^2e^x-2xe^x+7e^x ?

The derivative of x^2e^x-2xe^x+7e^x is e^xx^2+5e^x

What is the first derivative of x^2e^x-2xe^x+7e^x ?

The first derivative of x^2e^x-2xe^x+7e^x is e^xx^2+5e^x

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derivative of

x^{2} e^{x} - 2 x e^{x} + 7 e^{x}

e^{x} x^{2} + 5 e^{x}

Solution steps

\frac{d}{d x} (x^{2} e^{x} - 2 x e^{x} + 7 e^{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2} e^{x}) - \frac{d}{d x} (2 x e^{x}) + \frac{d}{d x} (7 e^{x})

\frac{d}{d x} (x^{2} e^{x}) = 2 x e^{x} + e^{x} x^{2}

\frac{d}{d x} (2 x e^{x}) = 2 (e^{x} + e^{x} x)

\frac{d}{d x} (7 e^{x}) = 7 e^{x}

= 2 x e^{x} + e^{x} x^{2} - 2 (e^{x} + e^{x} x) + 7 e^{x}

Simplify

2 x e^{x} + e^{x} x^{2} - 2 (e^{x} + e^{x} x) + 7 e^{x} : e^{x} x^{2} + 5 e^{x}

= e^{x} x^{2} + 5 e^{x}

x \to - 1 lim (x^{2} + 3 x + 2)

3 y^{^{''}} - 14 y^{^{'}} + 8 y = 0

\frac{d}{d x} (\frac{x ^{3}}{4 - x ^{2}})

\frac{d}{d x} (sec (x) tan (x) x (x + 1))

x^{3} \frac{d y}{d x} + 4 x^{2} y = e^{- x}

What is the derivative of x^2e^x-2xe^x+7e^x ?
The derivative of x^2e^x-2xe^x+7e^x is e^xx^2+5e^x
What is the first derivative of x^2e^x-2xe^x+7e^x ?
The first derivative of x^2e^x-2xe^x+7e^x is e^xx^2+5e^x