What is the derivative of 4t^{(-1)/8}+5ln(t)+ln(5) ?

The derivative of 4t^{(-1)/8}+5ln(t)+ln(5) is (10t^{9/8}-t)/(2t^{17/8)}

What is the first derivative of 4t^{(-1)/8}+5ln(t)+ln(5) ?

The first derivative of 4t^{(-1)/8}+5ln(t)+ln(5) is (10t^{9/8}-t)/(2t^{17/8)}

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derivative of

4 t^{\frac{- 1}{8}} + 5 ln (t) + ln (5)

\frac{10 t ^{\frac{9}{8}} - t}{2 t ^{\frac{17}{8}}}

Solution steps

\frac{d}{d t} (4 t^{\frac{- 1}{8}} + 5 ln (t) + ln (5))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (4 t^{\frac{- 1}{8}}) + \frac{d}{d t} (5 ln (t)) + \frac{d}{d t} (ln (5))

\frac{d}{d t} (4 t^{\frac{- 1}{8}}) = - \frac{1}{2 t ^{\frac{9}{8}}}

\frac{d}{d t} (5 ln (t)) = \frac{5}{t}

\frac{d}{d t} (ln (5)) = 0

= - \frac{1}{2 t ^{\frac{9}{8}}} + \frac{5}{t} + 0

Simplify

- \frac{1}{2 t ^{\frac{9}{8}}} + \frac{5}{t} + 0 : \frac{10 t ^{\frac{9}{8}} - t}{2 t ^{\frac{17}{8}}}

= \frac{10 t ^{\frac{9}{8}} - t}{2 t ^{\frac{17}{8}}}

n = 1 \sum \infty \frac{3}{5 ^{n}} + \frac{2}{n}

f (x) = 3 x^{2} - 4 x + 1

y = 4, y = x^{2}

\int 2 e^{- \frac{x}{2}} d x

\frac{d}{d x} (\frac{9 - sec ( x )}{tan ( x )})

What is the derivative of 4t^{(-1)/8}+5ln(t)+ln(5) ?
The derivative of 4t^{(-1)/8}+5ln(t)+ln(5) is (10t^{9/8}-t)/(2t^{17/8)}
What is the first derivative of 4t^{(-1)/8}+5ln(t)+ln(5) ?
The first derivative of 4t^{(-1)/8}+5ln(t)+ln(5) is (10t^{9/8}-t)/(2t^{17/8)}