What is the derivative of x^2-6(3)+9 ?

The derivative of x^2-6(3)+9 is 2x

What is the first derivative of x^2-6(3)+9 ?

The first derivative of x^2-6(3)+9 is 2x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

x^{2} - 6 (3) + 9

2 x

Solution steps

\frac{d}{d x} (x^{2} - 6 \cdot 3 + 9)

Simplify

x^{2} - 6 \cdot 3 + 9 : x^{2} - 9

= \frac{d}{d x} (x^{2} - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (9)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (9) = 0

= 2 x - 0

Simplify

= 2 x

3 x^{2} + 2

\int \frac{x}{4 x ^{2} + 1} d x

\int e^{\frac{t}{5}} d t

\int \frac{( x + 3 )}{x ^{2} + 8 x - 9} d x

x \to 2 - lim (\frac{x ^{2}}{x - 2})

What is the derivative of x^2-6(3)+9 ?
The derivative of x^2-6(3)+9 is 2x
What is the first derivative of x^2-6(3)+9 ?
The first derivative of x^2-6(3)+9 is 2x