What is the derivative of y= 4/(7x^2) ?

The derivative of y= 4/(7x^2) is -8/(7x^3)

What is the first derivative of y= 4/(7x^2) ?

The first derivative of y= 4/(7x^2) is -8/(7x^3)

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derivative of

y = \frac{4}{7 x ^{2}}

- \frac{8}{7 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{4}{7 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{4}{7} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{4}{7} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{4}{7} (- 2 x^{- 2 - 1})

Simplify

\frac{4}{7} (- 2 x^{- 2 - 1}) : - \frac{8}{7 x ^{3}}

= - \frac{8}{7 x ^{3}}

\frac{d y}{d x} = \frac{3 x ^{2}}{y ^{2}}

6 x^{2} + 5 x + 8, at x = 4

x \to 4 lim (x^{3} + 6 x)

x \to 2 lim (3 cos (x))

f (x) = x^{2} cos (\frac{1}{x})

What is the derivative of y= 4/(7x^2) ?
The derivative of y= 4/(7x^2) is -8/(7x^3)
What is the first derivative of y= 4/(7x^2) ?
The first derivative of y= 4/(7x^2) is -8/(7x^3)