What is the tangent of y= 5/x ,(4, 5/4) ?

The tangent of y= 5/x ,(4, 5/4) is y=-5/16 x+5/2

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tangent of y= 5/x ,(4, 5/4)

tangent of

y = \frac{5}{x}, (4, \frac{5}{4})

y = - \frac{5}{16} x + \frac{5}{2}

Solution steps

Find the slope of

y = \frac{5}{x} : \frac{d y}{d x} = - \frac{5}{x ^{2}}

Compute the slope of

y = \frac{5}{x}

(4, \frac{5}{4}) : m = - \frac{5}{16}

Find the line with slope m=

- \frac{5}{16}

and passing through

(4, \frac{5}{4}) : y = - \frac{5}{16} x + \frac{5}{2}

y = - \frac{5}{16} x + \frac{5}{2}

t^{2} \cdot t^{3} + 2

\frac{1}{2 r} + \frac{1}{9 r ^{\frac{8}{9}}}

\frac{d}{d x} (\frac{7}{1 + x})

n = 1 \sum \infty \frac{4}{n ^{2} + 1}

\int - 9.8 d x

What is the tangent of y= 5/x ,(4, 5/4) ?
The tangent of y= 5/x ,(4, 5/4) is y=-5/16 x+5/2