What is the solution for y^'=(x^8)/y ?

The solution for y^'=(x^8)/y is y=(sqrt(c_{1)+2x^9})/3 ,y=-(sqrt(c_{1)+2x^9})/3

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y^'=(x^8)/y

y^{^{'}} = \frac{x ^{8}}{y}

y = \frac{c _{1} + 2 x ^{9}}{3}, y = - \frac{c _{1} + 2 x ^{9}}{3}

Solution steps

y^{'} (x) = \frac{x ^{8}}{y}

Solve separable ODE:

y = \frac{c _{1} + 2 x ^{9}}{3}, y = - \frac{c _{1} + 2 x ^{9}}{3}

y = \frac{c _{1} + 2 x ^{9}}{3}, y = - \frac{c _{1} + 2 x ^{9}}{3}

\int x^{3} + 5 x - 1 d x

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What is the solution for y^'=(x^8)/y ?
The solution for y^'=(x^8)/y is y=(sqrt(c_{1)+2x^9})/3 ,y=-(sqrt(c_{1)+2x^9})/3