What is taylor ln(x+2),-1 ?

The answer to taylor ln(x+2),-1 is (x+1)-1/2 (x+1)^2+1/3 (x+1)^3-1/4 (x+1)^4+1/5 (x+1)^5+\ldots

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taylor ln(x+2),-1

taylor

ln (x + 2), - 1

(x + 1) - \frac{1}{2} (x + 1)^{2} + \frac{1}{3} (x + 1)^{3} - \frac{1}{4} (x + 1)^{4} + \frac{1}{5} (x + 1)^{5} + \dots

Solution steps

Apply the Taylor Formula

= 0 + \frac{\frac{d}{d x} ( ln ( x + 2 ) ) ( - 1 )}{1 !} (x + 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( ln ( x + 2 ) ) ( - 1 )}{2 !} (x + 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( ln ( x + 2 ) ) ( - 1 )}{3 !} (x + 1)^{3} + \dots

Evaluate Derivatives

= 0 + \frac{1}{1 !} (x + 1) + \frac{- 1}{2 !} (x + 1)^{2} + \frac{2}{3 !} (x + 1)^{3} + \frac{- 6}{4 !} (x + 1)^{4} + \frac{24}{5 !} (x + 1)^{5} + \dots

Refine

= (x + 1) - \frac{1}{2} (x + 1)^{2} + \frac{1}{3} (x + 1)^{3} - \frac{1}{4} (x + 1)^{4} + \frac{1}{5} (x + 1)^{5} + \dots

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What is taylor ln(x+2),-1 ?
The answer to taylor ln(x+2),-1 is (x+1)-1/2 (x+1)^2+1/3 (x+1)^3-1/4 (x+1)^4+1/5 (x+1)^5+\ldots