What is the integral from-3 to 3 of (9-x^2)^2 ?

The integral from-3 to 3 of (9-x^2)^2 is 1296/5

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integral from-3 to 3 of (9-x^2)^2

\int_{- 3}^{3} (9 - x^{2})^{2} d x

\frac{1296}{5}

Solution steps

\int_{- 3}^{3} (9 - x^{2})^{2} d x

Expand

(9 - x^{2})^{2} : 81 - 18 x^{2} + x^{4}

= \int_{- 3}^{3} 81 - 18 x^{2} + x^{4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 3}^{3} 81 d x - \int_{- 3}^{3} 18 x^{2} d x + \int_{- 3}^{3} x^{4} d x

\int_{- 3}^{3} 81 d x = 486

\int_{- 3}^{3} 18 x^{2} d x = 324

\int_{- 3}^{3} x^{4} d x = \frac{486}{5}

= 486 - 324 + \frac{486}{5}

Simplify

486 - 324 + \frac{486}{5} : \frac{1296}{5}

= \frac{1296}{5}

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x \to 0 lim (0)

\frac{d}{d x} (3 x^{7})

\int_{4}^{\infty} x e^{- x} d x

What is the integral from-3 to 3 of (9-x^2)^2 ?
The integral from-3 to 3 of (9-x^2)^2 is 1296/5