What is the solution for (dy)/(dx)-2/x y= 3/(x^2)y^4 ?

The solution for (dy)/(dx)-2/x y= 3/(x^2)y^4 is y=(\sqrt[3]{5}x^2)/(\sqrt[3]{-9x^5+c_{1)}}

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(dy)/(dx)-2/x y= 3/(x^2)y^4

\frac{d y}{d x} - \frac{2}{x} y = \frac{3}{x ^{2}} y^{4}

y = \frac{3 5 x ^{2}}{3 - 9 x ^{5} + c _{1}}

Solution steps

\frac{d y}{d x} - \frac{2}{x} y = \frac{3}{x ^{2}} y^{4}

Solve Bernoulli ODE:

y = \frac{3 5 x ^{2}}{3 - 9 x ^{5} + c _{1}}

y = \frac{3 5 x ^{2}}{3 - 9 x ^{5} + c _{1}}

\int_{1}^{2} 13 4 x^{2} - 3 d x

\frac{d}{d x} (- 5 x + 2)

\frac{\partial}{\partial y} (2 x - y^{2})

- \frac{5}{4 y ^{3}}

\frac{d}{d x} (cos (x^{- 5}))

What is the solution for (dy)/(dx)-2/x y= 3/(x^2)y^4 ?
The solution for (dy)/(dx)-2/x y= 3/(x^2)y^4 is y=(\sqrt[3]{5}x^2)/(\sqrt[3]{-9x^5+c_{1)}}