What is the d/(d{x)}({x}^2+{x}{z}-{y}+{y}^2+{y}{z}+3{z}^2) ?

The d/(d{x)}({x}^2+{x}{z}-{y}+{y}^2+{y}{z}+3{z}^2) is 2{x}+{z}-d/(d{x)}({y})

What is the first d/(d{x)}({x}^2+{x}{z}-{y}+{y}^2+{y}{z}+3{z}^2) ?

The first d/(d{x)}({x}^2+{x}{z}-{y}+{y}^2+{y}{z}+3{z}^2) is 2{x}+{z}-d/(d{x)}({y})

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\frac{d}{d x} (x^{2} + x z - y + y^{2} + y z + 3 z^{2})

2 x + z - \frac{d}{d x} (y)

Solution steps

\frac{d}{d x} (x^{2} + x z - y + y^{2} + y z + 3 z^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (x z) - \frac{d}{d x} (y) + \frac{d}{d x} (y^{2}) + \frac{d}{d x} (y z) + \frac{d}{d x} (3 z^{2})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x z) = z

\frac{d}{d x} (y^{2}) = 0

\frac{d}{d x} (y z) = 0

\frac{d}{d x} (3 z^{2}) = 0

= 2 x + z - \frac{d}{d x} (y) + 0 + 0 + 0

Simplify

= 2 x + z - \frac{d}{d x} (y)

\int x \cdot e^{\frac{x}{4}} d x

\frac{\partial}{\partial x} (4 \frac{y}{x})

\frac{d}{d y} (x y)

y = (x)

y = 4 x - 16, y^{2} = 4 x + 4

What is the d/(d{x)}({x}^2+{x}{z}-{y}+{y}^2+{y}{z}+3{z}^2) ?
The d/(d{x)}({x}^2+{x}{z}-{y}+{y}^2+{y}{z}+3{z}^2) is 2{x}+{z}-d/(d{x)}({y})
What is the first d/(d{x)}({x}^2+{x}{z}-{y}+{y}^2+{y}{z}+3{z}^2) ?
The first d/(d{x)}({x}^2+{x}{z}-{y}+{y}^2+{y}{z}+3{z}^2) is 2{x}+{z}-d/(d{x)}({y})