What is the derivative of y=x^2-2x-8 ?

The derivative of y=x^2-2x-8 is 2x-2

What is the first derivative of y=x^2-2x-8 ?

The first derivative of y=x^2-2x-8 is 2x-2

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derivative of

y = x^{2} - 2 x - 8

2 x - 2

Solution steps

\frac{d}{d x} (x^{2} - 2 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x) - \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (8) = 0

= 2 x - 2 - 0

Simplify

= 2 x - 2

\int (x^{2} + y) d x

\frac{d}{d y} (\frac{1}{y ^{2} + 1})

y^{^{'}} + 2 x y = 2 x^{3}

\frac{d}{d x} (\frac{x ^{2} - 3}{x + 2})

\int_{0}^{4} 4 x d x

What is the derivative of y=x^2-2x-8 ?
The derivative of y=x^2-2x-8 is 2x-2
What is the first derivative of y=x^2-2x-8 ?
The first derivative of y=x^2-2x-8 is 2x-2