What is (\partial)/(\partial x)(t/(x-1)) ?

The answer to (\partial)/(\partial x)(t/(x-1)) is -t/((x-1)^2)

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(\partial)/(\partial x)(t/(x-1))

\frac{\partial}{\partial x} (\frac{t}{x - 1})

- \frac{t}{( x - 1 ) ^{2}}

Solution steps

\frac{\partial}{\partial x} (\frac{t}{x - 1})

Treat

t

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= t \frac{\partial}{\partial x} (\frac{1}{x - 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= t \frac{\partial}{\partial x} ((x - 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x - 1 ) ^{2}} \frac{\partial}{\partial x} (x - 1)

= - \frac{1}{( x - 1 ) ^{2}} \frac{\partial}{\partial x} (x - 1)

\frac{\partial}{\partial x} (x - 1) = 1

= t (- \frac{1}{( x - 1 ) ^{2}} \cdot 1)

Simplify

t (- \frac{1}{( x - 1 ) ^{2}} \cdot 1) : - \frac{t}{( x - 1 ) ^{2}}

= - \frac{t}{( x - 1 ) ^{2}}

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\int \frac{tan ( x )}{1 + cos ( x )} d x

What is (\partial)/(\partial x)(t/(x-1)) ?
The answer to (\partial)/(\partial x)(t/(x-1)) is -t/((x-1)^2)