What is the tangent of y= 6/(sqrt(x)),(25, 6/5) ?

The tangent of y= 6/(sqrt(x)),(25, 6/5) is y=-3/125 x+9/5

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tangent of y= 6/(sqrt(x)),(25, 6/5)

tangent of

y = \frac{6}{x}, (25, \frac{6}{5})

y = - \frac{3}{125} x + \frac{9}{5}

Solution steps

Find the slope of

y = \frac{6}{x} : \frac{d y}{d x} = - \frac{3}{x ^{\frac{3}{2}}}

Compute the slope of

y = \frac{6}{x}

(25, \frac{6}{5}) : m = - \frac{3}{125}

Find the line with slope m=

- \frac{3}{125}

and passing through

(25, \frac{6}{5}) : y = - \frac{3}{125} x + \frac{9}{5}

y = - \frac{3}{125} x + \frac{9}{5}

\frac{x ^{2}}{7 + x}

x \to \infty lim (\frac{( 2 x ^{2} + 1 )}{3 x - 5})

y^{^{''}} - 2 y^{^{'}} = 2 t

x \to 3 + lim (\frac{x ^{2} + x}{x - 3})

cos (t + \frac{π}{4})

What is the tangent of y= 6/(sqrt(x)),(25, 6/5) ?
The tangent of y= 6/(sqrt(x)),(25, 6/5) is y=-3/125 x+9/5