What is the derivative of f(x)=3x^2+2x ?

The derivative of f(x)=3x^2+2x is 6x+2

What is the first derivative of f(x)=3x^2+2x ?

The first derivative of f(x)=3x^2+2x is 6x+2

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derivative of

f (x) = 3 x^{2} + 2 x

6 x + 2

Solution steps

\frac{d}{d x} (3 x^{2} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 x) = 2

= 6 x + 2

f (x) = sin^{2} (x) + cos^{2} (x)

\int_{1}^{2} 2 x d x

\frac{d}{d t} (s t^{2})

- 4 x^{2} - 3 x + 2, at x = - 1

\int \frac{1}{5 x ^{4}} d x

What is the derivative of f(x)=3x^2+2x ?
The derivative of f(x)=3x^2+2x is 6x+2
What is the first derivative of f(x)=3x^2+2x ?
The first derivative of f(x)=3x^2+2x is 6x+2