What is maclaurin (5+sqrt(5^2+4x^2))/2 ?

The answer to maclaurin (5+sqrt(5^2+4x^2))/2 is 5+1/5 x^2-1/125 x^4+2/3125 x^6-1/15625 x^8+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

maclaurin (5+sqrt(5^2+4x^2))/2

maclaurin

\frac{5 + 5 ^{2} + 4 x ^{2}}{2}

5 + \frac{1}{5} x^{2} - \frac{1}{125} x^{4} + \frac{2}{3125} x^{6} - \frac{1}{15625} x^{8} + \dots

Solution steps

Apply the Maclaurin Formula

= 5 + \frac{\frac{d}{d x} ( \frac{5 + 5 ^{2} + 4 x ^{2}}{2} ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( \frac{5 + 5 ^{2} + 4 x ^{2}}{2} ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( \frac{5 + 5 ^{2} + 4 x ^{2}}{2} ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 5 + \frac{0}{1 !} x + \frac{\frac{2}{5}}{2 !} x^{2} + \frac{0}{3 !} x^{3} + \frac{- \frac{24}{125}}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{\frac{288}{625}}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{- \frac{8064}{3125}}{8 !} x^{8} + \dots

Refine

= 5 + \frac{1}{5} x^{2} - \frac{1}{125} x^{4} + \frac{2}{3125} x^{6} - \frac{1}{15625} x^{8} + \dots

e^{x} + 17

\frac{d}{d x} (ln (\frac{cos ( x )}{sin ( x )}))

- e^{t} + \frac{1}{2} sin (t) + \frac{1}{2} cos (t)

\int cos (a x + b) d x

\int_{- 1}^{3} 6 x (x - 1) d x

What is maclaurin (5+sqrt(5^2+4x^2))/2 ?
The answer to maclaurin (5+sqrt(5^2+4x^2))/2 is 5+1/5 x^2-1/125 x^4+2/3125 x^6-1/15625 x^8+\ldots