en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=xe^x

Solution

y^{^{'}} = x e^{x}

Solution

y = e^{x} x - e^{x} + c_{1}

Solution steps

y^{'} (x) = x e^{x}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x e^{x} d x

\int x e^{x} d x = e^{x} x - e^{x} + c_{1}

y = e^{x} x - e^{x} + c_{1}

Popular Examples

integral from 0 to ln(4) of pi(e^{-x})^2

\int_{0}^{l n (4)} π (e^{- x})^{2} d x

(\partial)/(\partial x)((1+x^2)^{zsin(y)})

\frac{\partial}{\partial x} ((1 + x^{2})^{z s i n (y)})

(\partial)/(\partial y)(y^2ln(1+x^2+y^2))

\frac{\partial}{\partial y} (y^{2} ln (1 + x^{2} + y^{2}))

derivative of ln((xln(x-1)/(xln(x)+1)))

\frac{d}{d x} (ln (\frac{x ln ( x ) - 1}{x ln ( x ) + 1}))

tangent of f(x)=((x+1))/((x-1))tangent of

f (x) = \frac{( x + 1 )}{( x - 1 )}

Frequently Asked Questions (FAQ)

What is the solution for y^'=xe^x ?
The solution for y^'=xe^x is y=e^xx-e^x+c_{1}