What is the derivative of y=x^2+2x-3 ?

The derivative of y=x^2+2x-3 is 2x+2

What is the first derivative of y=x^2+2x-3 ?

The first derivative of y=x^2+2x-3 is 2x+2

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derivative of

y = x^{2} + 2 x - 3

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x) - \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (3) = 0

= 2 x + 2 - 0

Simplify

= 2 x + 2

\int \frac{e ^{x} ( x - 1 )}{x ^{2}} d x

\int \frac{1}{3 cos ( x ) - 4 sin ( x )} d x

\frac{d ^{2}}{d x ^{2}} (\frac{e ^{x}}{x})

x \to - 3 - lim (\frac{∣ x + 3 ∣}{x + 3})

x \to - 8 - lim (\frac{x + 3}{x + 8})

What is the derivative of y=x^2+2x-3 ?
The derivative of y=x^2+2x-3 is 2x+2
What is the first derivative of y=x^2+2x-3 ?
The first derivative of y=x^2+2x-3 is 2x+2