What is the derivative of f(x)=4x^2+3x ?

The derivative of f(x)=4x^2+3x is 8x+3

What is the first derivative of f(x)=4x^2+3x ?

The first derivative of f(x)=4x^2+3x is 8x+3

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derivative of

f (x) = 4 x^{2} + 3 x

8 x + 3

Solution steps

\frac{d}{d x} (4 x^{2} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (3 x) = 3

= 8 x + 3

y^{^{''}} + 2 y^{^{'}} + 2 y = sin (9 x)

\frac{1}{X ^{2}}

\frac{4 ( - s + 16 )}{s ^{2} + 10 s}

(- 4.5) (2.3)

\frac{d}{d x} ((x^{2} ln (x))^{4})

What is the derivative of f(x)=4x^2+3x ?
The derivative of f(x)=4x^2+3x is 8x+3
What is the first derivative of f(x)=4x^2+3x ?
The first derivative of f(x)=4x^2+3x is 8x+3