What is the derivative of y= 1/3 cos((6pix-1)/2) ?

The derivative of y= 1/3 cos((6pix-1)/2) is -pisin((6pix-1)/2)

What is the first derivative of y= 1/3 cos((6pix-1)/2) ?

The first derivative of y= 1/3 cos((6pix-1)/2) is -pisin((6pix-1)/2)

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derivative of

y = \frac{1}{3} cos (\frac{6 π x - 1}{2})

- π sin (\frac{6 π x - 1}{2})

Solution steps

\frac{d}{d x} (\frac{1}{3} cos (\frac{6 π x - 1}{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (cos (\frac{6 π x - 1}{2}))

Apply the chain rule:

- sin (\frac{6 π x - 1}{2}) \frac{d}{d x} (\frac{6 π x - 1}{2})

= - sin (\frac{6 π x - 1}{2}) \frac{d}{d x} (\frac{6 π x - 1}{2})

\frac{d}{d x} (\frac{6 π x - 1}{2}) = 3 π

= \frac{1}{3} (- sin (\frac{6 π x - 1}{2}) \cdot 3 π)

Simplify

\frac{1}{3} (- sin (\frac{6 π x - 1}{2}) \cdot 3 π) : - π sin (\frac{6 π x - 1}{2})

= - π sin (\frac{6 π x - 1}{2})

\int - e^{x} - \frac{7}{cos ^{2} ( x )} d x

\frac{d}{d x} (sin (x^{2} cos (x)))

\frac{d}{d x} (cot^{2} (3 - 2 x))

\int \frac{3}{2} e^{\frac{3}{2} x} d x

f (x) = 9 - x^{2}

What is the derivative of y= 1/3 cos((6pix-1)/2) ?
The derivative of y= 1/3 cos((6pix-1)/2) is -pisin((6pix-1)/2)
What is the first derivative of y= 1/3 cos((6pix-1)/2) ?
The first derivative of y= 1/3 cos((6pix-1)/2) is -pisin((6pix-1)/2)