What is the solution for (dy)/(dt)=(yt-y)/((r^2+1)) ?

The solution for (dy)/(dt)=(yt-y)/((r^2+1)) is y=e^{(t^2-2t)/(2(r^2+1))+c_{1}}

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(dy)/(dt)=(yt-y)/((r^2+1))

\frac{d y}{d t} = \frac{y t - y}{( r ^{2} + 1 )}

y = e^{\frac{t ^{2} - 2 t}{2 ( r ^{2} + 1 )} + c_{1}}

Solution steps

\frac{d y}{d t} = \frac{y t - y}{( r ^{2} + 1 )}

Solve separable ODE:

y = e^{\frac{t ^{2} - 2 t}{2 ( r ^{2} + 1 )} + c_{1}}

y = e^{\frac{t ^{2} - 2 t}{2 ( r ^{2} + 1 )} + c_{1}}

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What is the solution for (dy)/(dt)=(yt-y)/((r^2+1)) ?
The solution for (dy)/(dt)=(yt-y)/((r^2+1)) is y=e^{(t^2-2t)/(2(r^2+1))+c_{1}}