What is the integral of 4ln(9x^2) ?

The integral of 4ln(9x^2) is 4(2xln(3x)-2x)+C

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integral of 4ln(9x^2)

\int 4 ln (9 x^{2}) d x

4 (2 x ln (3 x) - 2 x) + C

Solution steps

\int 4 ln (9 x^{2}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int ln (9 x^{2}) d x

Apply Integration By Parts

: x ln (9 x^{2}) - \int 2 d x

= 4 (x ln (9 x^{2}) - \int 2 d x)

\int 2 d x = 2 x

= 4 (x ln (9 x^{2}) - 2 x)

Simplify

ln (9 x^{2}) : 2 ln (3 x)

= 4 (2 x ln (3 x) - 2 x)

Add a constant to the solution

= 4 (2 x ln (3 x) - 2 x) + C

\int z ln (2)

\int e^{l n (x)} d x

\frac{d y}{d x} = 2 y + 1 cos (x)

(\frac{( x + 3 )}{( x - 1 )})^{2}

x \to 3 + lim (3 x - 7)

What is the integral of 4ln(9x^2) ?
The integral of 4ln(9x^2) is 4(2xln(3x)-2x)+C