What is the integral from-1 to 0 of 1/x ?

The integral from-1 to 0 of 1/x is diverges

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integral from-1 to 0 of 1/x

\int_{- 1}^{0} \frac{1}{x} d x

diverges

Solution steps

\int_{- 1}^{0} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{- 1}^{0}

Compute the boundaries:

diverges

= diverges

\frac{d}{d x} (\frac{3}{2} sin (2 x))

\int (x^{2} - y) d x

\frac{d}{d x} (2 sin (x))

\int x csc^{2} (4 x) d x

\int_{- 1}^{1} 0.09375 (4 - x^{2}) d x

What is the integral from-1 to 0 of 1/x ?
The integral from-1 to 0 of 1/x is diverges